Question

Calculate the amount of each reactant required to produce 950 mL of
carbon dioxide according to the following equation:

2 CO + 02 -> 2 CO2​

Answer 1

In the above above Question , the following information is given -

Calculate the amount of each reactant required to produce 950 mL of carbon dioxide according to the following equation :

$\sf{ 2 CO + O_2 \leftrightharpoons 2CO_2 }$

Observe the above reaction carefully .

Here , we Know that -

22.4 litre of gas occupies 1 mole at STP

=> 1 litre of gas occupies ( 1 / 22.4 ) mole at STP

=> 0.95 litres of gas occupies ( 1 / 22.4 ) × 0.95 mole at STP

=> 0.424 moles approximately .

Now ,

2 mole CO is required to produce 2 mole CO2

So ,

1 mole CO2 is produced by 1 mole CO

So ,

0.0424 moles of CO2 is produced by 0.0424 moles of CO

=> So ,

Amount Of CO required -

=> 0.0424 moles .

Now ,

Number of moles = [ Given Mass / Molar Mass ]

=> 0.0424 = [ Given Mass / 44 ]

=> Given Mass Of CO

=> 1.8656 grams .

Hence , 1.8656 grams of CO is required for the reaction .

Now ,

1 mole O2is required to produce 2 mole CO2

So ,

1 mole CO2 is produced by ( 1 / 2 ) mole O2

So ,

0.0424 moles of CO2 is produced by 0.0212 moles of CO

=> So ,

Amount Of O2 required -

=> 0.0212 moles .

Now ,

Number of moles = [ Given Mass / Molar Mass ]

=> 0.0212 = [ Given Mass / 32 ]

=> Given Mass Of O2

=> 0.6784 grams .

Hence , 0.6784 grams of O2 is required for the reaction .

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Answer 2

In the above above Question , the following information is given -

Calculate the amount of each reactant required to produce 950 mL of carbon dioxide according to the following equation :

$\huge \tt 2 CO + O_2 \leftrightharpoons 2CO_2$

Observe the above reaction carefully .

Here , we Know that -

22.4 litre of gas occupies 1 mole at STP

=> 1 litre of gas occupies ( 1 / 22.4 ) mole at STP

=> 0.95 litres of gas occupies ( 1 / 22.4 ) × 0.95 mole at STP

=> 0.424 moles approximately .

Now ,

2 mole CO is required to produce 2 mole CO2

So ,

1 mole CO2 is produced by 1 mole CO

So ,

0.0424 moles of CO2 is produced by 0.0424 moles of CO

=> So ,

Amount Of CO required -

=> 0.0424 moles .

Now ,

Number of moles = [ Given Mass / Molar Mass ]

=> 0.0424 = [ Given Mass / 44 ]

=> Given Mass Of CO

=> 1.8656 grams .

Hence , 1.8656 grams of CO is required for the reaction .

Now ,

1 mole O2is required to produce 2 mole CO2

So ,

1 mole CO2 is produced by ( 1 / 2 ) mole O2

So ,

0.0424 moles of CO2 is produced by 0.0212 moles of CO

=> So ,

Amount Of O2 required -

=> 0.0212 moles .

Now ,

Number of moles = [ Given Mass / Molar Mass ]

=> 0.0212 = [ Given Mass / 32 ]

=> Given Mass Of O2

=> 0.6784 grams .

Hence , 0.6784 grams of O2 is required for the reaction .

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