Question

Calculate the amount of electric energy available from a dry cell of EMF 1.5 V which consumes 30 g of Zn​

Answer 1

Answer:

n(Zn) = \frac{6.55}{65.5}65.56.55 = 0.1 (mol)

E = UQ = E(2nF) = 1.5(2\times×0.1\times×96485) = 28945.5 J.

Answer 2

Answer:

n(Zn) = \frac{6.55}{65.5}65.56.55 = 0.1 (mol)

E = UQ = E(2nF) = 1.5(2\times×0.1\times×96485) = 28945.5 J.

Explanation:

PLS MARK ME AS BRAINLIST.