Question

Calculate the amount of energy needed to raise the
temperature of 3.0 kg of steel from 20 °C to 120 °C. The
specific heat capacity of steel is 490 J kg-1 K-1. please answer with a step by step with your answer and with all formulas filled in.​

Answer 1

Here mass(M) = 3kg

change in temperature(ΔT)= 120K-20K

                                     = 100*C

                                   c= 490 J Kg-1 K-1

                                  Q= McΔT

                                 490 × 3 × 100

                                 147000 J Ans.

Hence 14700 J of heat energy needed to raise the temperature of 3 kg of steel from 20K to 120K (or in degree celsius one and the same thing)

Answer 2

Explanation:

✳Answer✳

✳↕️↕️↕️✳

✳147000 J Ans.✳