Calculate the amount of energy released in ergs, calories and in joules when 0.001 kg of mass disappears.
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Heya....✋
✨According to Einstein equation, E=mc^2
m= 0.001 kg= 1×10^-3 kg; c=3×10^8 m/s
E= (1×10^-3)(3×10^8)= 9×10^13 J
1 J= 10^7 erg= 0.24 cal
9×10^13 J= 9×10^13×10^7 erg= 9×10^20 erg
=9×10^13×0.24 cal= 2.16×0^13 cal
Hope it helps✅
✨According to Einstein equation, E=mc^2
m= 0.001 kg= 1×10^-3 kg; c=3×10^8 m/s
E= (1×10^-3)(3×10^8)= 9×10^13 J
1 J= 10^7 erg= 0.24 cal
9×10^13 J= 9×10^13×10^7 erg= 9×10^20 erg
=9×10^13×0.24 cal= 2.16×0^13 cal
Hope it helps✅
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