calculate the amount of energy required to to convert 2kg of water at 34°C to ice to 0°C
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Total heat = Heat required to convert 2Kg of ice into water at 0°C + Heat required to convert 2Kg of water at 0°C to 2Kg of water at 20°C.
Heat = m (hfw) + mc∆T.
Here, m(mass of ice) = 2Kg.
hfw (specific latent heat of water) = 3,34,000J/Kg.
C (specific heat capacity of water) = 4200JKg-1 K-1
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