Question

Calculate the amount of F.A.S. required to prepare M/20 standard solution of F.A.S.
ans.​

Answer 1

Answer:

Ans is - 20.0 ML

Explanation:

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Answer 2

The amount of F.A.S. required to prepare M/20 standard solution of F.A.S. is 19.6g.

Explanation:

• Molarity:  Molarity is defined as the number of moles of solute dissolved per unit volume of the solution. Mathematically, it can be expressed as,M = n/V

where M = Molarity of the solution

n = Number of moles of solute

V = Volume of the solution

The number of moles of solute is given by,

n = m/W

where m = Mass of the solute in grams

W = Molar mass of the solute

• Here solute is ferrous ammonium sulphate (or Mohr's salt) [(NH₄)₂ Fe (SO₄) ₂ · 6H₂O].
• Molar mass of solute, W = 2(Molar mass of NH₄) + Molar mass of Fe + 2(Molar mass of SO₄) + 6(Molar mass of H₂O)
• Molar mass of solute, W = 2(18) + 56 + 2(96) + 6(18)

                                      = 36 + 56 + 192 + 108                                    

                                      = 392 g/mol

• Let the mass of solute in grams be w.
• Now, molarity is given 1/20 M. This means that 1/20 moles are dissolved per unit volume.
• Number of moles of solute, n = 1/20
• But n = m/W
• ∴ m/W = 1/20
• m = W/20
• m = 392/20
• m = 19.6 g
• Amount of f.a.s., m = 19.6 g

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