Question

calculate the amount of F. A. S. required to prepare M/20 standard solution of F. A. S. ​

Answer 1

Answer:

Observation

ObservationWeight of watch glass = 50.498 g.

ObservationWeight of watch glass = 50.498 g.Weight of watch glass + Mohr's salt = 4.9 g.

ObservationWeight of watch glass = 50.498 g.Weight of watch glass + Mohr's salt = 4.9 g.Weight of Mohr's salt = 4.90 g.

ObservationWeight of watch glass = 50.498 g.Weight of watch glass + Mohr's salt = 4.9 g.Weight of Mohr's salt = 4.90 g.Volume of Mohr's salt solution prepared = 250 ml.

ObservationWeight of watch glass = 50.498 g.Weight of watch glass + Mohr's salt = 4.9 g.Weight of Mohr's salt = 4.90 g.Volume of Mohr's salt solution prepared = 250 ml.Molarity of Mohr's salt solution = M/20.

ObservationWeight of watch glass = 50.498 g.Weight of watch glass + Mohr's salt = 4.9 g.Weight of Mohr's salt = 4.90 g.Volume of Mohr's salt solution prepared = 250 ml.Molarity of Mohr's salt solution = M/20.Volume of Mohr's salt solution taken for each titration = 20.0 ml.

Answer 2

Answer:

19.6 g

Explanation:

Given: Molarity = M/20

To find: Mass of F.A.S. to prepare M/20 solution

Explanation:

F.A.S represents Ferrous ammonium sulphate ($FeSO_{4} .(NH_{4} )_{2} SO_{4}.6 H_{2} O$).

Molar mass of F.A.S. = 392 g/mol

Now, molarity is defined as-

$Molarity =\frac{Moles\ of\ solute}{Volume\ of\ solution\ in\ L}$

If the volume is assumed to be 1 L, that means to prepare a standard solution, a fixed mass of F.A.S. is added to 1 L of water and the molarity of the solution depends directly on moles (or mass).

Thus, for M//20 , we must have moles/20.

Now, 1 mole of F.A.S. = 392 g

So, Moles/20 of F.A.S.= $\frac{392\ g}{20} = 19.6 g$

Hence, the amount of F.A.S. required to prepare M/20 standard solution = 19.6 g.

Prepare m/20 solution of oxalic acid

https://brainly.in/question/8048631

Prepare m/20 solution of ferrous ammonium sulphate and find molarity and strength

https://brainly.in/question/8008475

#SPJ2