Question

calculate the amount of glucose present in 500 ml of m/2 glucose solution

Answer 1

Answer:

Given, 500ml C

6

H

12

O

6

contains 6.02×10

22

molecules

We know 1 mole of C

6

H

12

O

6

contains 6.02×10

23

molecules

∴ No. of moles having 6.02×10

22

molecules=

6.02×10

23

6.02×10

22

=0.1 moles

Now, Molarity=

VinL

No.ofmoles

=

0.5L

0.1mol

=0.2M