Question

calculate the amount of glucose required for preparing 500ml of 0.1M solution ​

Answer 1

Explanation:

Molarity = 0.1, Molecular weight of glucose = 180, Volume of solution = 500 ml

Weight of solute =Molarity × Gram molecular weight of solute × vol of solin ml1000=Molarity × Gram molecular weight of solute × vol of solin ml1000

Weight of solute =0.1×180×5001000=9 g ∴ Weight of glucose=9 g