Question

calculate the amount of heat absorbed by 100g of ice change into water of 30°c.ans(11000)

Answer 1

Answer:

sol:-

heat absorbed by of ice=100

it changes into water =30

the amount=100-30

=70

(or)

=100+30

=70

Answer 2

Answer:3000 cal.

Explanation:

Mass(m) =100g

Temp. Difference(∆T) =30°c

Specific heat capacity (C) =1 kcal/kg°c

To find: HEAT ENERGY(Q)

FORMULA: Q=mc∆T

Solution:

Q=mc∆T

=100×1×30

=3000 cal