Question

calculate the amount of heat energy required to convert 0.025 kg of ice at 0°C to water at 100°C​

Answer 1

Answer:

We know that, to change the state of a matter, heat is required.

Heat required to change a solid into liquid is given by ,

Q=mL ,

where L= latent heat of fusion ,

now given that , m=0.025kg ,

and latent heat of fusion of ice is , L=336×10^3 J/kg ,

hence, heat required to convert the 0.025kg of ice at 0°C to water at 0°C ,

Q=(0.025×336×10^3)= 8400kJ ,

now, heat required to convert the 0.025kg of water at 0°C to water at 100°C ,

we know that,

Q1=m×c×Δt ,

given c=4200J/kg°C ,

hence Q1 = 0.025×4200×(100−0)=10500 kJ ,

therefore total heat required to convert the 0.025kg of ice at 0°C to water at 100°C,

total heat = Q + Q1 = 8400+10500 = 18900 KJ

Hope it helps u...