Question

calculate the amount of heat generated when 7200C of charge is transferred in one hour through a potential difference of 50v​

Answer 1

⇝GIVEN:-

➔ Charge Q = 7200C

➔ Time t = 1 hr

= 60×60 = 3600 sec

➔ Potential Difference V = 50 V

⇝TO FIND:-

➔ Amount of heat generated = ?

⇝SOLUTION:-

We know,

$\tt current \: is \: given \: by$

$\tt ✣ I = \frac{Q}{t}$

$\tt ⇾ I = \frac{ \cancel{7200}} { \cancel{3600}} =2 \: A$

Now,

$\tt resistance \: is \: given \: by$

$\tt ⛥ R = \frac{V}{I}$

$\tt ↬R = \frac{ \cancel{50}}{ \cancel{2}} = 25 \: Ω$

Now,

$\tt heat \: generated \: is \: given \: by$

$\tt ❂ H = {I}^{2} \: R T$

$\tt ⤑ H = {2}^{2} \times 25 \times 3600$

$\tt ⤑ H = 4 \times 90000$

$\tt ⤑ H = 360000$

$\tt☄Hence, \: we \: get \: heat \: generated , H = \fcolorbox{pink}{white}{360k J.}$