Question

Calculate the amount of heat generated while transferring 18000 coulomb of charge between the two terminal of a battery of 50V in one hour

Answer 1

Answer:

C=18000

V=50v

T=1hour

firstly we have to find the current

so (I=Q/T)

I=18000/60*60

I=5A

Now,we have to calculate the resistance-

V=IR

so,R= V/I

R=50/5

R=10ohm

Now, Heat=I^2*R*T

H=5^2*10*60*60

H=25*36000

H= 900000Joule

Answer 2

The amount of heat generated is 900000 J.

Explanation:

The heat generated in the circuit is given as

$H=i^2Rt$

Here, i is the current in the circuit, R is the resistance and t is the time.

The current i, charge q and time t is related as

$i=\frac{q}{t}$

Given q = 18000 C and t = 1 h =3600 s.

So, $i=\frac{18000C}{3600s}$

i = 5 A

now use ohm`s law to get the resistance in the circuit,

$R=\frac{V}{i}$

$R=\frac{50V}{5A} =10\Omega$

Therefore,

$H= (5A)^2\times10\Omega\times3600s$

$H=9.0\times10^5J$.

Thus, the amount of heat generated is 900000 J.

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