Calculate the amount of heat generated while transferring 90000 coulombs
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Calculate the amount of heat generated while transferring 90000 coulomb of charge between the two terminal of a battery of 40V in one hour. also determine the power expended in the process.
Q=90000coulombs,
T=1hour=3600
seconds,V=40 volt
I=Q/T=90000/3600=25Amperes
R=V/I=40/25=1.6 ohms
H=I×I×R×T=25×25×1.6×3600
=3600 kilojoule
P=I×I×R=25×25×1.6=1000watt=1kilowatt.
Answered by
7
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- Q=90000coulombs,
- T=1hour=3600 seconds,
- V=40 volt
- I=Q/T=90000/3600=25Amperes
- R=V/I=40/25=1.6 ohms
- H=I×I×R×T=25×25×1.6×3600
- =3600 kilojoule
- P=I×I×R=25×25×1.6=1000watt=1kilowatt.
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