Question

calculate the amount of heat generated while transferring 90000 coulomb of charge between the two terminal of a battery of 40V in one hour. also determine the power expended in the process

Answer 1

Ans)Q=90000coulombs,T=1hour=3600 seconds,V=40 volt

I=Q/T=90000/3600=25Amperes
R=V/I=40/25=1.6 ohms
H=I×I×R×T=25×25×1.6×3600
=3600 kilojoule
P=I×I×R=25×25×1.6=1000watt=1kilowatt.

Answer 2

=90000coulombs,T=1hour=3600 seconds,V=40 volt

I=Q/T=90000/3600=25Amperes

R=V/I=40/25=1.6 ohms

H=I×I×R×T=25×25×1.6×3600

=3600 kilojoule

P=I×I×R=25×25×1.6=1000watt=1kilowatt.