Question

Calculate the amount of heat given out while 400 g of water at 30 °C is cooled and converted into ice at -2 °C. Specific heat capacity of water = 4200 J/kg K Specific heat capacity of ice = 2100 J/ kg K Specific latent heat of fusion of ice = 336000 J/kg

Answer 1

Mass of water = 400 g = 0.4 kg

Initial temperature of water = 30°C

Final temperature of water = 0°C

Final temperature of ice = -2°C

Ф for water = 30°C

Ф for ice = 2°C

Heat required = mcФ (water) + mL + mcФ (ice)

where Ф is change in temperature and L is latent heat of fusion

                       = 0.4 × 4200 × 30 + 0.4 × 336000 + 0.4 × 2100 × 2

                       = 50400 + 13400 + 1680

                       = 65480 J

Answer 2

Answer:

Explanation:

Calculate the amount of heat given out while 400 g of water at 30 °C is

cooled and converted into ice at -2 °C.

Specific heat capacity of water = 4200 J/kg K

Specific heat capacity of ice = 2100 J/ kg K

Specific latent heat of fusion of ice = 336000 J/kg