Question

Calculate the amount of heat released by 1 gram mercury to change phase from liquid to solid. The heat of fusion for mercury is 11.8 x 103 J/kg.

Answer 1

Answer By Amit

Known :

Mass (m) = 1 gram = 1 x 10-3 kg

Heat of fusion (LF) = 11.8 x 103 J/kg

Wanted : Heat (Q)

Solution :

Q = m LF

Q = (1 x 10-3 kg)(11.8 x 10

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3 J/kg)

Q = 11.8 Joule

Answer 2

Given - Mass and heat of fusion

Find - Amount of heat released

Solution - The amount of heat released = mass*heat of fusion.

As per the known fact, 1000 gram = 1 kilogram

1 gram = ${10}^{ - 3}$ kg

Keep the values in formula

Amount of heat released = ${10}^{ - 3} \times 11.8 \times {10}^{3}$

Performing multiplication and adding powers

Amount of heat released = 11.8 Joules.

Hence, the amount of heat released in phase change is 11.8 Joules.