calculate the amount of heat released when 5 g of water at 20 degree c is changed into ice at 0 degree c?
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Answer:
Total amount of heat released = 1680 J + 420 J = 2100 J.
Explanation:
Answered by
1
ANSWER:
Heat energy =mcΔT+mL
where, m = mass of water
c = specific heat capacity of water
L = specific latent heat of fusion of ice
ΔT = change in temperature
Therefore, heat energy released =5×4.2×20+5×336=420+1680 =2100J.
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