Calculate the amount of heat required to change 100 g of ice at 0° C to steam at 100° C. given that latent heat of fusion of ice is 80 cal g ^ -1 ; specific heat of water = 1 cal g ^ -1 ° C ^ -1 ; latent heat of vaporisation of steam = 540 cal g ^ -1
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formula Q=mc∆T
here c = 540+80=620
put the value if the ans the answer is correct then the way is correct
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