Question

Calculate the amount of heat required to change 100 g of ice at 0°C to steam at 100°C. Given that latent heat of fusion of ice is 80 cal g1; specific heat of water = 1 cal g1°C1; latent heat of vapourisation of steam = 540 cal g1. ​

Answer 1

Answer:

72000cal or 72kcal.

Explanation:

It is explained in the picture, hope it helps!