Question

calculate the amount of heat required to convert 10 gram of ice into water at zero degree celsius into steam​

Answer 1

Answer:

6200 Cal or 26040 J

Explanation:

from ice to water at 0*c

10*80 Cal (m*lf)

from water at 0*c to water at 100*c

10*1*100 Cal (m*s*∆t)

from water to steam at 100*c

10*540 Cal (m*lv)

adding all we get 6200cal

plz mrk as brainliest