Calculate the amount of heat required to convert 15 gram of ice at - 10°C into steam.
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The answer to this question is :
Latent heat of fusion of water = 334 J / kg.
Q = M*L*T
Q = 15/1000*334*10
Q = 50.10 joules
Q = 50 joules (approximately)
Hope this answer will help you!
Thank You!
Latent heat of fusion of water = 334 J / kg.
Q = M*L*T
Q = 15/1000*334*10
Q = 50.10 joules
Q = 50 joules (approximately)
Hope this answer will help you!
Thank You!
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