Question

calculate the amount of heat required to
convert 5g of
of ice of 0℃ into water at 0℃
(specific latert heat of fusion of ice = 80 cal/g .)​

Answer 1

600cal

Amount of heat required=latent heat of ice+heat required to convert water from 0oC to 40oC

=mLi+mcΔT

=5[80+1(40−0)]

=400+200=600cal

Explanation:

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