Question

Calculate the amount of heat required to raise the temperature of 25 gm. Of water through 30°C
Sp. Heat of water = 4200 j/kg-k

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Answer 1

Q=mass×specific heat× Change in heat

Q=25×4200×(273+30)

Q=1050×303

Answer 2

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➡ Q =

$= mass \: \times \: specific \: heat \: \times \: \\ change \: in \: heat \\ = 25 \times 4200 \times (273 + 30) \\ = 1050 \times 303$