Question

Calculate the amount of heat required to raise the temperature of 1gm of water to1'c

Answer 1

Solution Heat required = Mass of ice [latent heat of

fusion + 8 profit of heat × temp change +

Latent heat of boiling ]

⇒ΔH=1g[L f +8(ΔT)+Lv ]

ΔH=1g[80cal/g+1cal/g(100−0)+540calg]

ΔH=[80+100+540]=7200

Hole its helpful.❤

Answer 2

Solution Heat required = Mass of ice [latent heat of

fusion + 8 profit of heat × temp change +

Latent heat of boiling ]

⇒ΔH=1g[L f +8(ΔT)+Lv ]

ΔH=1g[80cal/g+1cal/g(100−0)+540calg]

ΔH=[80+100+540]=7200

Hope its helpful.✔