Question

Calculate the amount of heat transferred when 550 grams of water cools from an initial temperature of 25.0 ºC to a final temperature of 4.0 ºC. The specific heat capacity of liquid water is 4.184 J/g ºC. Please express you answer as a number in units of kJ, and be careful about the sign (positive or negative number?) since that shows the direction of heat flow.

Answer 1

Answer:

Explanation:

To calculate the energy required to raise the temperature of any given substance, here's what you require:

The mass of the material,

m

The temperature change that occurs,

Δ

T

The specific heat capacity of the material,

c

(which you can look up). This is the amount of heat required to raise 1 gram of that substance by 1°C.

Here is a source of values of

c

for different substances:

http://www2.ucdsb.on.ca/tiss/stretton/Database/Specific_Heat_Capacity_Table.html

Once you have all that, this is the equation:

Q

=

m

×

c

×

Δ

T

(

Q

is usually used to symbolize that heat required in a case like this.)

For water, the value of

c

is

4.186

J

g

°

C

So,

Q

=

750

×

4.186

×

85

=

266

858

J

=

266.858

k

J

Answer 2

Answer: -48.3 kj

Explanation: