Calculate the amount of heat transferred when 710 grams of water warms from an initial temperature of 4.0 ºC to a final temperature of 25.0 ºC. The specific heat capacity of liquid water is 4.184 J/g ºC. Please express you answer as a number in units of kJ, which is already provided after the answer box, and be careful about the sign (is the answer a positive or negative number?) since that shows the direction of heat flow.
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Answer:
Q = 62383.44 Joules
Explanation:
Given that,
Mass of water, m = 710 gm
Initial temperature of water,
Final temperature of water,
The specific heat capacity of liquid water is,
Heat transferred is given by :
Q = 62383.44 Joules
So, the amount of heat transferred is 62383.44 Joules. Hence, this is the required solution.
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