Question

Calculate the amount of HI produced when 127g of I2 to react with 10g of H2

Answer 1

Answer:

In the reaction, H

2

(g)+I

2

(g)⇌2HI(g), in a 2 litre flask 0.4 mole of each H

2

and I

2

are taken. At equilibrium 0.5 mol of HI are formed. The value of equilibrium constant K

c

will be 11.1.

0.5 moles of HI will be obtained from 0.25 moles of H

2

and 0.25 moles of I

2

.

0.4−0.25=0.15 moles of H

2

and 0.4−0.25=0.15 moles of I

2

will remain.

The equilibrium constant

K

c

=

[H

2

][I

2

]

[HI]

2

K

c

=

(

2 L

0.15 mol

)×(

2 L

0.15 mol

)

(

2 L

0.5 mol

)

2

Kc =11.1