Question

calculate the amount of hydrogen gas produced from the reaction of 65grams of pure zinc with dil H₂SO4​

Answer 1

Answer:

$65$ g of pure zinc reacted with dilute sulphuric acid produce $4$ g of dihydrogen gas·

Explanation:

The balanced chemical equation for the formation of hydrogen gas is,

$Zn\ +\ H_2SO_4\ --->\ ZnSO_4\ +\ 2\ H_2$

Given that,

The amount of pure zinc taken  $=$  $65$ g

From the balanced chemical equation, it is clear that  

One mole of zinc reacted with one mole of dilute sulphuric acid produces one mole of zinc sulphate and two moles of dihydrogen gas·

One mole of zinc weigh $65$ g which is the atomic mass of the zinc·

One mole of dihydrogen weigh $2$ g·

Then,

Two moles of dihydrogen weigh $4$ g·

Therefore,

$65$ g of pure zinc reacted with dilute sulphuric acid produce $4$ g of dihydrogen gas·