Calculate the amount of ice that will separate out on cooling a solution containing 50g of ethylene glycol in 200g of water to -9.3 °C. Molal depression constant for water is 1.86 K kg/mol
kvnmurty:
cooled from which temp?
Answers
Answered by
45
Molal depression constant = Depression in Kelvin per mole of solute present in kg of solvent.
molecular mass of Ethylene Glycol = C2 H6 O2 = 62 gm/mole
Number of moles/kg of water = 50 /62 * 1000/200 = 4 moles/kg
Actual depression in freezing point temperature: 1.86 °K * 4 = 7.44°K
Specific heat of Ice = 2 J/gm-°K
Heat released from 200gm of water(ice) due to lowering of temperature
= 7.44 * 2 * 200 = 2, 976 J
Latent heat of fusion of ice = 334 kJ /kg = 334 J/gm
Amount of ice that will melt away due to availability of 2, 976 J:
= 2,976/334
= 8.91 gm
molecular mass of Ethylene Glycol = C2 H6 O2 = 62 gm/mole
Number of moles/kg of water = 50 /62 * 1000/200 = 4 moles/kg
Actual depression in freezing point temperature: 1.86 °K * 4 = 7.44°K
Specific heat of Ice = 2 J/gm-°K
Heat released from 200gm of water(ice) due to lowering of temperature
= 7.44 * 2 * 200 = 2, 976 J
Latent heat of fusion of ice = 334 kJ /kg = 334 J/gm
Amount of ice that will melt away due to availability of 2, 976 J:
= 2,976/334
= 8.91 gm
click on red heart thanks above pls
Answered by
11
Explanation:
both the pictures are the same answer.
the answer is continued in the second page
Attachments:
Similar questions