calculate the amount of KClO3 needed to supply sufficient oxygen for burning 112L of CO at NTP.
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Explanation:
We get 2.5 moles of Oxygen from 2.5*2/3 = 5/3 moles of KClO3. Answer: 204.6 g of KClO3 is needed to supply sufficient oxygen for burning 112L of CO at STP.
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1
Answer:
Calculate the amount of KClO3 which on thermal decomposition gives ‘X’ vol. of O2 , which is the volume required for combustion of 24 g. of carbon. [K = 39, Cl = 35.5, O = 16, C = 12]
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