calculate the amount of lime formed when 60g of calcium carbonate is heated. (the atomic masses are; ca=40,c=12,o=16)
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Explanation:
Chemical reaction involved is:
CaCO3 →CaO+CO2
Molar mass of CaCO3 =40+12+16×3=100 g
According to the balanced reaction 100 g of CaCO3 produces 1 mol of CO2 i.e. 22.4 L at STP.
∴50g CaCO3 will produce 22.4/100 ×50=11.2 L CO2 at STP.
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