Calculate the amount of lime required to remove the hardness of 20L of pond water containing 3 mg of calcium
bicarbonate per 100 ml of water (0.27 g)
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Answer:
The naswer is 0.274 g
Explanation:
Ca(HCO3) + Ca(OH)2 ------> 2CaCO3 + 2H2O
Weight of Ca(HCO3) presetnt if 20L of pond water = 3 x 10^-3 x 20 x 10^3 / 100 = 0.6 g
162 g Ca(HCO3) requires 74 g of Ca(OH)2
0.6 g of Ca(HCO3) requires = 74 x 0.6 / 162 = 44.4 /162 = 0.274 g
Thus 0.274 g of lime is required to remove the hardness of pond water.
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