calculate the amount of lime soda reqired for softening of 100000 liters of water using 139 ppm of feso4
Answers
Answer:
1ppm =0.07^@
Clark <br> So, ppm of all constituents are <br>
CaCO_3=20ppm, MgCO_3=8ppm, CaSO_4=6ppm
, <br>
MgSO_4=22ppm, MgCl_2=0.5ppm, and NaCl=0.5ppm
<br>
NaCl=0.5ppm
has no constibution for hardness so it has no contribution towards
CACO_3
equivalents,
CaCO_3=20
ppm as
CaCO_3
. <br>
MgCO_3=8ppm=(8xx100)/(84)=9.523 ppm CaCO_3Eq
<br>
CaSO_4=6ppm=(6xx100)/(136)=4.417ppmCaCO_3Eq
<br>
MgSO_4=2ppm=(2xx100)/(120)=1.666ppmCaCO_3Eq
<br>
MgCl_2=0.5ppm=(0.5xx100)/(95)=0.5263ppmCaCO_3Eq
<br>
NaCl=0.5ppm=
no contribution to hardness. <br> Lime requirement: <br>
=(74)/(100)
[Temporary Ca hardness
+2xx
Temporary Mg hardness
+
permanent Mg hardness] <br>
=(74)/(100)[20+2xx9.523+1.666+0.5263]
<br>
=(74xx41.2383)/(100)=30.5163ppm
<br>
=30.5163mgL^(-1)=30.4163xx10^(6)(mg)/(10^(6))L
<br> Soda requirment <br>
(106)/(100)
[Permanent Ca hardness
+
permanent Mg hardness
+
free acids
-HCO_3^(ɵ)
] <br>
=(106)/(100)[4.417+1.666+0.5263]=7.0ppm=7.0mgL^(-1)
<br>
=7.0xx10^(6)mg10^(6)L^(-1)=7.0kg