Question

calculate the amount of limestone needed to prepare 100g of co2​

Answer 1

Limestone or CaCO3 when heated liberates CO2 and CaO

CaCO3 --------> CO2 + CaO

Since the equation is balanced,

1 mole CO2 => 1 mole CaCO3

no: of moles of CO2 required = 100/44 = 25/11 moles

Hence,

25/11 moles CO2 => 25/11 moles CaCO3

n = Given mass/ Molar mass

25/11 = Given mass/100 (Molar mass of CaCO3 = 100)

Given mass = 25×100/11 = 227.27 g

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