Calculate the amount of Mg required to prepare 10 gram of Mg3N2 .
(2Mg+N2–>Mg3N2)
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hey buddy,,,,
given: 10g of Mg3N2
Amount of Mg=?
then for mass of Mg= molar mass of Mg3N2/10
100/10= 10g....
then, SIMILARLY mass of magnesium required== 24/10= 2.4g ..
❇❇be brainlyyy
given: 10g of Mg3N2
Amount of Mg=?
then for mass of Mg= molar mass of Mg3N2/10
100/10= 10g....
then, SIMILARLY mass of magnesium required== 24/10= 2.4g ..
❇❇be brainlyyy
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