Calculate the amount of MgO formed by heating 25 g of MgCO3
MgCO3 MgO + CO2 (Atomic weight of C = 12, 0 = 16, Mg=24)
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Answer:
Molar mass of mgco3 is 84
Moles of mgco3 = 25/84
Moles of mgo = 25/84
Mass of mgo = 25/84 x (24+16)=12g
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