calculate the amount of O2 required for the combustion of 32 gram of Methane
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Hola mate.....Here is your answer....
CH4 + 2O2 ----> CO2 + 2H2O
Here, 1 mol of CH4 requires 2 moles of oxygen fr combustion....
So, 16 gm CH4, requires 64 grams of oxygen
If we use 32 gram of methane, we will require 128 gm oxygen for combustion...
Hope u understood ^_^
CH4 + 2O2 ----> CO2 + 2H2O
Here, 1 mol of CH4 requires 2 moles of oxygen fr combustion....
So, 16 gm CH4, requires 64 grams of oxygen
If we use 32 gram of methane, we will require 128 gm oxygen for combustion...
Hope u understood ^_^
Anu726:
thank you
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