Question

Calculate the amount of Oxygen gas produced on heating 12. 25 of KCL O3

Answer 1

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KClO Decomposes to give KCl and O
2KClO → 2KCl +3O
Molecular weight of KClO is 39 +35.3+40 = 122.5
Here 2 moles of KClO has taken, Hence molecular weight = 2X122.5 = 245
According to the equation 245g of KClO Produces 3 moles of Oxygen
i.e 3X22.4 L = 67.2 L of oxygen is produced
245g of KClO → 67.2 L of oxygen
12.25 g of KClO → ? oxygen
= 12.25 X 67.2/245
=3.36 L
Volume of Oxygen released = 3.36 L

Answer 2

KClO3 Decomposes to give KCl and O2
2KClO3 → 2KCl +3O2
Molecular weight of KClO3 is 39 +35.3+40 = 122.5
Here 2 moles of KClO3 has taken, Hence molecular weight = 2X122.5 = 245
According to the equation 245g of KClO3 Produces 3 moles of Oxygen
 i.e 3X22.4 L = 67.2 L of oxygen is produced
245g of KClO3 → 67.2 L of oxygen
12.25 g of KClO3 → ? oxygen
= 12.25 X 67.2/245
 =3.36 L
Volume of Oxygen released = 3.36 L