Question

calculate the amount of particles in 46g of Na atom

Answer 1

a)46g of Na atom

atomic mass of Na=23u

Number of particles=Number of Moles x N

⇒(given weight/ Gram atomic weight) x 6.023 x 10²³

=(46/23)x 6.023 x 10²³

=2x 6.023 x 10²³

⇒12.046 x 10 ²³Na particles

∴46 g of Na contains 12.044 x 10 ²³

Answer 2

Molar mass of Na = 23g

23g of Na = 1 mole

46g of Na = 46/23= 2mole of Na

1 mole = 6.022*10^23 atoms

2 mole = 2*6.022*10^23= 12.044*10^23 atoms of Na