Question

calculate the amount of SO2 released from 1000mg of KMS​

Answer 1

Answer:

I am literally really sorry I don't know

Answer 2

Given:

mass of kms( potassium metabisulphite) = 1000mg = 10g

To Find:

the amount of SO2 released =?

Solution:

Now, we know that the reaction of kms with water yields  SO2, water and potassium ion on complete hydrolysis.

thus, the reaction involved is

$K_{2} S_{2} O_{5} + H2O$ → 2KHSO3

Thus, 1 mol kms gives 2 mol SO2

also the molar mass of kms = 222g

the molar mass of SO2 = 64g

222 g kms gives 2 × 64g SO2

10 g kms gives $\dfrac{2 \times 64 \times10}{222}$g SO2

= 5.76 g SO2

thus, the amount of SO2 released = 5.76g