Question

calculate the amount of sodium chloride required to adjust solution of containing 40 mEq each of potassium and chloride ions per litre to iso osmotic with blood plasma​

Answer 1

Answer:

2.34g

Explanation:

So Molarity of KCl =  40 × 10⁻³ M

  40 ml K⁺ and 40 ml Cl⁻ present in 1 litre

So Molarity of NaCl =  40 × 10⁻³ M

moles  of NaCl =  40 × 10⁻³

weight  of NaCl =  40 × 10⁻³ ( 23 + 35.5 )

weight  of NaCl =  58.5 × 40 × 10⁻³

weight  of NaCl =  $\frac{2340}{1000}$

weight  of NaCl= 2.34g

Hope this will help you...