Question

Calculate the amount of sodium hydroxide in 100ml of 0.1(M) NaOH solution

Answer 1

Acc. To me,

Your answer is 0.4g

Molarity=mole/volume(L)

1000ml=1L

1ml=1/1000L

100ml=100/1000L=>1/10L

molarity(M)=0.1

put in formula

0.1=n/0.1

n=0.01

n=weight/molar mass

molar mass of NaOH=40

0.01=m/40

m=0.4g

I hope it help

Answer 2

Answer:

0.4g

Explanation:

using the formula of molarity

m=(w/m')×(1000/v)

0.1=(w/40)×(1000/100)

w=0.4g