Question

Calculate the amount of sodium hydroxide present in 5L its

decimolar solution​

Answer 1

Explanation:

Molarity (M) : The number of moles of a solute dissolved in 1 L (1000 ml) of the solution is known as the molarity of the solution.

Molarity of a solution

(M)=

molar mass of solute

mass of solute

​

×

volume of solution in mL

1000

​

∴0.2=

40

w

​

×

500

1000

​

so w=4gm.

Amount of sodium hydroxide present in 500ml of 0.2M solutions is 4 gm.