Question

calculate the amount of sodium oxide formed when 2.3g of sodium reacts with 3.2g of oxygen?​

Answer 1

Answer:

Correct option is

B

22.4g

The molar mass of Na

2

SO

4

.10H

2

O is

2(23)+32+4(16)+10(18)=322 g/mol.

1 mole of Na

2

SO

4

.10H

2

O contains 14 moles of O atoms.

1 mole of Na

2

SO

4

.10H

2

O corresponds to 14×16=224 g of O.

Amount of oxygen in 32.2g of Na

2

SO

4

.10H

2

O is 32.2×224322=22.4 g

Explanation:

please make as brilliant

Answer 2

Explanation:

the answer is in the attachment