Question

Calculate the amount of sodium Sulphate to prepare 400 ml 1 / 4 (M) solution.​

Answer 1

Answer:

14.2 g

Explanation:

Given,

V = 400 ml = 0.4 L

Molarity = 1/4 M = 0.25 M

Amount [in grams] = ?

Molarity = no. of moles[n] / volume[in L]

=> 0.25 = n / 0.4

=> n = 0.1 mole

No. of moles = Given mass[w] / Molar mass[M]

=> 0.1 = w/M

[M for Na₂SO₄ = 2 x 23 + 32 + 4 x 16 = 142]

=> 0.1 = w/142

=>w = 142 x 0.1 = 14.2 g

Please mark BRAINLIEST