Calculate the amount of solute (in grams) present in 1 litre of 0.5 gm equivalent per litre of NaOH solution and also, calculate
the amount of solvent present in total amount of solution if the density of the solution is 0.5gm/cm .
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The molar mass of NaOH is 40 g/mol.
The number of moles of NaOH is equal to the ratio of its mass to molar mass.
The number of moles of NaOH =
40g/mol
40g
=1mol
The molarity of NaOH solution is the ratio of number of moles of NaOH to total volume of solution in L.
M=
1L
1mol
=1M
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