Question

calculate the amount of water (g) produced by the combustion of 48 g of methane​

Answer 1

Answer:

According to the above equation, one mole of CH4 (48 g) on combustion gives one mole of carbon dioxide and 2 moles of water and 2 moles of water = 2 x(2+48)=52 gram of methane

Explanation:

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