Calculate the amount of water (g) produced by the combustion of 60 g of ethane.
Answers
:2×[2+16]=36 gram of the water
Explanation:
one molecule of (CH4) 16gm on combution gives one molecule of carbon dioxide and 2 molecule of water and 2 moles of water=2×[2+16]=36 gram of the water
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The amount of water (g) produced by the combustion of 60 g of ethane is 54 g.
Given: The amount of ethane: 60 g
To find: Amount of water (g) produced by the combustion
Solution:
The reaction of combustion of ethane:
+
⇒
+
Moles of ethane produced from 60g of ethane= Amount of ethane ÷ molecular weight of ethane
Molecular weight of ethane = 30g/mol
Moles of ethane produced from 60g of ethane= 60g ÷ 30g/mol = 2moles
2 moles of produces 6 moles of
1 mole produces 3 moles of
Amount of water produced by 1 mole of = 3 × 18 g = 54 gm.
Hence, The amount of water (g) produced by the combustion of 60 g of ethane is 54 g.
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