Chemistry, asked by dhairyajain110, 7 months ago

Calculate the amount of water (g) produced by the combustion of 60 g of ethane.

Answers

Answered by shankarpatil4324
0

:2×[2+16]=36 gram of the water

Explanation:

one molecule of (CH4) 16gm on combution gives one molecule of carbon dioxide and 2 molecule of water and 2 moles of water=2×[2+16]=36 gram of the water

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Answered by PravinRatta
0

The amount of water (g) produced by the combustion of 60 g of ethane is 54 g.

Given: The amount of ethane: 60 g

To find: Amount of water (g) produced by the combustion

Solution:

The reaction of combustion of ethane:

2C_{2} H_{6} + 7O_{2}4CO_{2} + 6H_{2} O

Moles of ethane produced from 60g of ethane= Amount of ethane ÷ molecular weight of ethane

Molecular weight of ethane = 30g/mol

Moles of ethane produced from 60g of ethane= 60g ÷ 30g/mol = 2moles

2 moles of C_{2} H_{6} produces 6 moles of H_{2} O

1 mole  C_{2} H_{6} produces 3 moles of H_{2} O

Amount of water produced by 1 mole of C_{2} H_{6} = 3 × 18 g = 54 gm.

Hence, The amount of water (g) produced by the combustion of 60 g of ethane is 54 g.

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