Question

Calculate the amount of water (g) produced by the combustion of 16g of methane.

Answer 1

$\boxed{ \bf \: Hello \: Rehan \: Bhai }$

we know when methane reacts with oxygen to forms carbon dioxide and water , so it's very easy for us to solve it nicely xD

$\bf Balanced \: formula \: for combustion \: of \: methane$

→ 1 CH4 + 2O+ CO 2 + 2H2O

here we can see easily

• 16 gms of methane is equal to one mole

[ by the formula ]

• And the main point is that 1 mol of methane gives 2 mol of water isn't it ?

$\bf Trick :- \:$

To find the mol in any equation just see the times of any compound

for example :- 2H2O has 2 mol because it is multiplied with 2 . and same for others too

We can conclude

2 Mol of water ( H2O ) = 2 × ( 2 + 16 ) = 36 gms

1 mol of water = 18g × water

$=> \frac{18g \times water}{1mol \: of \: water \: }$

This is how ,

$2mol \: of \: water \: \times \frac{18g \: of \: water \: }{1mol \: of \: water \: } \\ \\ = \boxed{ \bf 2 \times 18 = 36g \: of \: water}$

Hope this helps you ☺

Answer 2

Answer:

• According to the above equation, one mole of CH4 (16 g) on combustion gives one mole of carbon dioxide and 2 moles of water and 2 moles of water = 2 x [2 + 16] = 36 g of water.